Calculation of nagios latency in nagiostas

Yueh-Hung Liu yuehung.liu at gmail.com
Tue Feb 22 03:13:14 CET 2011


because at any moment in physical, not all checks will be performed,
therefore Nagios only knows the "previous" average latency and the
latency of services which have just finished.
Nagios won't keep the latency of checks in somewhere so it has to
calculate the "present" average latency right after each check while
it has the newest latency of that check in hand.
you can see the formula that while the total latency is restored, the
number of checks will be decreased by 1, that means the latency of the
check just finished will be added to calculate new average latency.
this method can make sure the average latency is "dynamical" and "real time".


On Tue, Feb 22, 2011 at 8:25 AM, Yu Watanabe <yu.watanabe at jp.fujitsu.com> wrote:
> Hello all.
>
> I would like to ask question for the calculation with nagios latecy.
> In the nagiostats.c , the calculation of 'average_active_service_latency' is
> not doing the simple way, which is
>
> 1. Add up the latecy of each service
> 2. Devide by the number of services
>
> rather than above it is caculating as,
>
> average_active_service_latency=(((average_active_service_latency*((double)active_service_checks-1.0))+latency)/(double)active_service_checks);
>
> 1. Revert the average sum by multiplying the previous average and number of checks
> 2. Add up the latency of the current line
> 3. Devide by the number of services
>
> Would there be a specific reason or thought in this calculation?
>
> Thanks,
> Yu Watanabe
>
>
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Collect, index and harness all the fast moving IT data generated by your 
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Deliver compliance at lower cost and gain new business insights. 
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