skiplist insert free?

[hiren]

thanks.
I'm a bit confused about why it could be correct though, from what I see
the function uses "update" and frees it at the end just before returning
anyway. from what I understand the function uses "update" only for
itself either way?

On Sun, 2008-09-28 at 16:54 +0200, Andreas Ericsson wrote:
> hirenp wrote:
> > Hi,
> > 
> > I'm wondering if this is a valid submission:
> > 
> 
> I'll look into it. If the skiplist api copies the passed data,
> then it's correct (as the caller will never have a pointer to
> the data in that case). If the api doesn't, then it's wrong,
> as the caller may need to do something else with the pointer
> when the skiplist insertion fails.
> 


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